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Lab Report on Diffraction | Physics Assignment Helpers

Objective

  • To understand the diffraction of light using a red laser

Abstract

The detector angle 2ϴ records the diffraction peak position. This position of the diffraction peaks are determined by the distance between parallel planes of atoms. The x-ray wavelength of most diffractometer is fixed. Calculating the wavelength of a red laser, the following equation is used: Lambda = (a*x)/d, Lambda is the wavelength in meters, a is the distance between the slits, x is the fringe separation and D distance between the screen and the grating. The grating is known to have 500 lines per mm thus this means 500,000lines per m.1/500,000 to get distance between them 2µm. Now wavelength can be calculated using the above equation.

A= 0.00004 m,d = 0.00025m x= 2*10^-9 m

Wavelength= 0.00004*2*10^-9/0.00025

= 3.2*10-7m

Equipment

The equipment used were a laser beam and a diffractometer.

Data

PeaksPosition(x ,y)Peak separation
10.0720m, 0.478%0.0121m
20.0743m, 1.02%0.0098m
30.0767m, 1.69%0.0074m
40,0792m, 2.40%0.0049m
50.0818m, 2.85%0.0023m
60.0841m, 3.03%0.0000m
70.0866m,2.72%0.0025m
80.0891m, 2.15%0.0050m
90,0915m, 1.44%0.0074m
100.0940m, 0.796%0.0099m

Screenshots of coordinates.

Analysis

Wavelength calculations

Wavelength = a*X/d

A=0.04mm or o.00004m, d= 0.25 mm or 0.00025 m, x= 1/500,000= 2µm

0.00004*2µm/0.00025= 3.2*10^-7m

Wavelength = 3.2*10-7m

Percentage error= (calculated value- accepted value/ accepted value)*100

320nm-640nm/640nm)*100= 50%

Conclusion

From the data collected above there was a percentage error of the wavelength calculated, which was 50%.Looking at the calculations the measurements did not lie within the maximum and minimum bounds though they were consistent. Even with such unaccounted errors the representation of the actual wavelength was fair and demonstrated a good presentation of diffraction of red light.

When two speakers are put at opposite ends of a room. The two sound s waves travel through the air spreading out through the room in a spherical manner. These two waves interfere in such a way they produce loud sound in some locations and no sound in other locations. The loud sounds are as a result of compressions meeting compressions or rarefactions meeting rarefactions, and for the no sounds appear in locations where rarefaction of one wave meets compressions of another wave.

 

Cite this Page

Lab Report on Diffraction | Physics Assignment Helpers . (2021, December 23). Essay Writing . Retrieved November 27, 2022, from https://www.essay-writing.com/samples/lab-report-on-diffraction/
“ Lab Report on Diffraction | Physics Assignment Helpers .” Essay Writing , 23 Dec. 2021, www.essay-writing.com/samples/lab-report-on-diffraction/
Lab Report on Diffraction | Physics Assignment Helpers . [online]. Available at: <https://www.essay-writing.com/samples/lab-report-on-diffraction/> [Accessed 27 Nov. 2022].
Lab Report on Diffraction | Physics Assignment Helpers [Internet]. Essay Writing . 2021 Dec 23 [cited 2022 Nov 27]. Available from: https://www.essay-writing.com/samples/lab-report-on-diffraction/
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